I will be taking some time off work to prep the frontage of my house and would really appreciate any advise. I have got 80 square metres of Indian slate (about 30-50mm thick) that i will more than likely be paying a professional to lay,as i want a good finished job and i dont feel confident enough to do it myself.
I will be hiring a concrete breaker for the existing concrete drive to be broken up and a small 750mm wide mini digger to clear the frontage ,What i need to know is how deep to go down with the digger and what material I.E. hard core,type 1,sub base,(bearing in mind i will be driving cars on it)do i put any plastic sheeting down first, what's the easiest way to level the sub base before using a whacker plate, how much room do i leave for the the slate and the sand/cement.
i would appreciate any info and tips given to me (in simple terms aswell please)
The finshed level needs to be 150mm down from the DPC Paul. If the existing concrete drive was in good condition with no dips or cracks then a sub base may not ne necessary as the existing one was obviously doing its job. If not, then 100mm of scalpings would be required. ( See the project on Garden Makeover to view scalpings) and these must go onto a solid ground base. Any damp spots can be dug out and filled with the concrete you are breaking up. No plastic sheeting is necessary but a weed fabric would be good. This allows water through, but not light, and can be bought from the toolstore. Scalpings can be levelled with the digger blade or a shovel and then compacted to refusal, i.e. they will not go down any more. 50mm of sharp sand and cement to lay the slate, mixed at 8 sand to 1 cement. Keep the mix fairly dry (you should be able to squeeze a lump in your hand so that it stays together but no water squeezes out) and this will give it a little flexibility and its really important its is mixed well, in a mixer. If lumps of sand are allowed to stay "umixed" they will breakdown with water and form voids in the base, the mix around the voids collapses into the void = dip in surface.
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